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7v^2-11v-10=0
a = 7; b = -11; c = -10;
Δ = b2-4ac
Δ = -112-4·7·(-10)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{401}}{2*7}=\frac{11-\sqrt{401}}{14} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{401}}{2*7}=\frac{11+\sqrt{401}}{14} $
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